2NO (g)+O2(g)=2NO2(g) kimyasal denge eşitliği?

Here rate law is given as:-
rate=k[NO]2[O2​]...(1)
[NO](concentration of NO) can be written as Vn​
where n=number of moles and V=volume
From (1)
rate=K[Vn​]2[Vn​]...(2)
Now,
Volume is related to 1/3rd
From V to 3V​
put new volume in (2)
New rate will be
r′=K[V3n​]2[V3n​]=K (3)2[Vn​]2(2)[Vn​]=27K[V3n​]2[V3n​]so, rr′​=K[Vn​]2[Vn​]27K[V3n​]2[V3n​]​=27​
Rate of reaction changes by 27 times.

Soru ne?